Question

in a triangle the sum of 2 angles is 118 and their difference is 32 find each angle of the triangle

Answer 1

Let the two angles be x and y where x > y
their sum is 118 ⇒ x + y = 118
their difference is 32 ⇒ x - y = 32

Adding these two equations, we get
 2x = 150
x = 75
substitute x = 75 in x - y = 32 and solving, we get y = 43

We know that,
Sum of the three angles of a triangle is 180 degrees

The third angle = 180 - (118) = 62

Answer 2

Answer:Suppose the two angles of triangle are x and y.

Now according to the question we have;

x+y = 118 ...(i)And; x−y = 32 ...(ii)x+y = 118 ...(i)And; x-y = 32 ...(ii)

Adding (i) and (ii) we get;

x+y+x−y = 118+32⇒2x = 150⇒x = 75x+y+x-y = 118+32⇒2x = 150⇒x = 75

Then from (i) we get;

y = 118−75 = 43y = 118-75 = 43

And we know that the sum of the angles of triangle is 180. so we have;

Third angle = 180 - (75 + 43) = 62

Therefore the angles of triangle are 43°, 62° and 75°

Step-by-step explanation: