IN A TRIANGLE, THE SUM OF 2 ANGLES IS EQUAL TO THE THIRD. IF THE DIFFERENCE BETWEEN THEM IS 50°, DETERMINE THE ANGLES.
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let A, B and C the angles of triangles
A+B+C=180---------(equation 1)
A+B=C----------(equation 2)
put the 2nd equation in the 1st equation.
C+C=180
2C=180
C=180\2
C=90
Hence other two are 45
A+B+C=180---------(equation 1)
A+B=C----------(equation 2)
put the 2nd equation in the 1st equation.
C+C=180
2C=180
C=180\2
C=90
Hence other two are 45
salehabaseer9:
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Answered by
1
Let angles = a, b, c
a+b = c
sum of all angles of triangle = 180
a+b+c = 180
c+c = 180
2c = 180
c = 90
hence, a+b = 90
a+a-50 = 90 ( difference= 50, b= a-50)
2a = 140
a = 70
b= 70 - 50 = 20
c = 90
a+b = c
sum of all angles of triangle = 180
a+b+c = 180
c+c = 180
2c = 180
c = 90
hence, a+b = 90
a+a-50 = 90 ( difference= 50, b= a-50)
2a = 140
a = 70
b= 70 - 50 = 20
c = 90
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