In a triangle, the sum of angles (2x + 5)º and (3x+10) i
at most 90°. Find the maximum value of the angles. 2.this answer will be 35and 55
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if they are complementary angle then the sum of them will 90°.
thus,
(2x-5)° + (x-10)° =90°
2x-5+x-10=90°
3x-15=90°
3x=90+15
3x=105
x=105÷3
x=35°. ans
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xhfifvjg 36966 458.558,09*955,9*8
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