in a triangle the sum of the two angles is equal to third. If first angle is double of the second angle, determine the angle?
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Let the angles be x,y and z.
Therefore, according to question (A•T•Q), 2 (angle x) = angle y.
As well as, angle x + angle y = angle z
Thus, x + 2x = z
3x = z
x = z/3.
Again, 2 (angle x) = angle y
But x = z/3
Therefore, angle y = 2z/3
Now we know that,
x + y + z = 180°
Therefore, z/3 + 2z/3 + z = 180°
6z/3 = 180°
6z = 180 into 3
z = 90.
Therefore, angle z= 90
angle x = 30
angle y = 60
Therefore, according to question (A•T•Q), 2 (angle x) = angle y.
As well as, angle x + angle y = angle z
Thus, x + 2x = z
3x = z
x = z/3.
Again, 2 (angle x) = angle y
But x = z/3
Therefore, angle y = 2z/3
Now we know that,
x + y + z = 180°
Therefore, z/3 + 2z/3 + z = 180°
6z/3 = 180°
6z = 180 into 3
z = 90.
Therefore, angle z= 90
angle x = 30
angle y = 60
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