Question

In a triangle, the sum of two angles is 118 degrees and their difference is 32 degrees.find each angle of the triangle.

Answer 1

x + y = 118°
x - y = 32°
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2x = 150°
x = 75°
y = 118° - x = 118° - 75° = 43°

x + y + z = 180°
z = 180° - 118° = 62°

Answer 2

Answer:

Suppose the two angles of triangle are x and y.

Now according to the question we have;

x+y = 118 ...(i)And; x−y = 32 ...(ii)x+y = 118 ...(i)And; x-y = 32 ...(ii)

Adding (i) and (ii) we get;

x+y+x−y = 118+32⇒2x = 150⇒x = 75x+y+x-y = 118+32⇒2x = 150⇒x = 75

Then from (i) we get;

y = 118−75 = 43y = 118-75 = 43

And we know that the sum of the angles of triangle is 180. so we have;

Third angle = 180 - (75 + 43) = 62

Therefore the angles of triangle are 43°, 62° and 75°

Step-by-step explanation: