Question

In a triangle, the sum of two angles is equal to the third. If the difference between them is 50, find the angles

Answer 1

Hii

you are welcome in my ans

x1+x2 =x3----(1

x1 - x2 =50----(2

x1 +x2 +x3=180

2x3 =180

x3 =90

on adding ---1 and ------2

2x1 =120

x1=60

x2 =30

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Hope it may helps you

Answer 2

SOLUTION

Let the three angle be a,b&c with c as the longest angle.

Now,

A+B=C

A+B-C= 0..........(1)

A-B= 50............(2)

Also,

A+B+C = 180°

(angle sum property of∆).........(3)

Subtracting equation(3) from (1), we get

=) -2C= -180°

=) C= -180°/-2

=)C= 90°

Now, putting this value in equation (1),

A+B= 90°..........(4)

A-B= 50......(from 2)

Subtracting equation (2) from (1),we get

=) 2B= 80

=) B= 80/2

=) B= 40°

Putting this value of B in eq (1)

=) A+B-C= 0

=) A+40- 90=0

=) A= (90-40)°

=) A= 50°

Hence, the angles of the ∆ are 90°,40° & 50°

hope it helps ☺️