Question

In a triangle XYZ, let x, y, z be the lengths of sides opposite to the angles X, Y, Z, respectively, and
2s = x + y + z. If s-x/4 = s-y/3 = s - z/2 and area of incircle of the triangle XYZ is 8????/3, then
(A) area of the triangle XYZ is 6√6
(B) the radius of circumcircle of the triangle XYZ is 35/6 √6
(C) sin X/2 sin Y/2 sin Z/2 = 4/35
(D) sin² ( X + Y/2) = 3/5

Answer 1

Answer:

5

Step-by-step explanation:

5