Question

in a triangle xyz x=78,y=z find y​

Answer 1

Answer:

$let \: y = z = a \\ in \: triangle \: xyz \\ we \: know \\ x + y + z = 180 \\ 78 + a + a = 180 \\ 2a = 102 \\ a = 51$

so y = 51

Answer 2

Answer:

(i) Draw a line segment which is sufficiently long using ruler.

(ii) Locate points X and Z on it such that XZ=9.5cm.

(iii) With X as centre and radius 7.8cm, draw an arc(see figure)

(iv) With Z as centre and radius 4.5cm , draw another arc cutting the previous arc at C.

(v) Join XY and YZ

Then ABC is the required triangle.

solution