Math, asked by dhruvshadilya4462, 1 year ago

in a triangle XYZ xy=4.8cm,angle x=60'.angle y=70'.draw the triangle and construct circumcircle.

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Answered by Anonymous
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Answered by CarlynBronk
43

In Δ x y z

x +y +z= 180°

60 ° + 70° +z= 180°

z= 180° - 130°

z= 50°

→Draw line segment XY of length = 4.8 cm

→At, x draw angle ∠x=60°, and at y, draw ∠y=70°.

→The point where the rays X A and Y B meet is Point Z.

→This is required triangle X Y Z.

→→To draw the Circumcircle of ΔX Y Z Draw perpendicular bisector of any of two sides of ΔX Y Z.

The point where these perpendicular bisector meet is circumcenter of ΔX Y Z.

→Mark circumcenter as point O.

→Join OX,OY and OZ.Taking any of OX, OY or OZ as radius draw circumcircle which passes through Vertices of Δ X Y Z.


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