Math, asked by vibek5628, 10 months ago

In a triangle xyz,xy =7cm,yz=24cm and xz=25cm. Find the length of the perpendicular from vertics y to side xz?

Answers

Answered by RvChaudharY50
1

Given :- In a triangle xyz, xy = 7cm, yz = 24cm and xz = 25cm.

To Find :-

  • The length of the perpendicular from vertics y to side xz ?

Solution :-

checking if given sides satisfies the pythagoras condition ,

Let ,

  • XY = Perpendicular of ∆XYZ
  • YZ = Base of ∆XYZ .
  • XZ = Hypotenuse of ∆XYZ .

so,

→ XY² + Y² = XZ² (By pythagoras theorem.)

→ 7² + 24² = 25²

→ 49 + 576 = 625

→ 625 = 625 .

therefore, we can conclude that,

  • ∆XYZ is a right angled ∆.

then,

→ Area of Right angled ∆XYZ = (1/2) * Base * Perpendicular height .

Now, Let us assume that, the perpendicular from vertics Y to side XZ(Hypotenuse) is h cm.

therefore,

→ (1/2) * Base(YZ) * Perpendicular height(XY) = (1/2) * Base(XZ) * Perpendicular height(h)

→ (1/2) * 24 * 7 = (1/2) * 25 * h

→ 24 * 7 = 25 * h

→ 25h = 168

→ h = (168/25)

→ h = 6.72 cm. (Ans.)

Hence, the perpendicular from vertics Y to side XZ is 6.72 cm.

Learn more :-

In ABC, AD is angle bisector,

angle BAC = 111 and AB+BD=AC find the value of angle ACB=?

https://brainly.in/question/16655884

Similar questions