Question

In a triangleABC, AB parpendicular
BC,
ACB = 30° AB - 15 m, then find the length of
BC
30​

Answer 1

Answer:

BC=15√3

Step-by-step explanation:

since the angles are 30 and 90,the third angle would be 60.

therefore,

the side opposite the 90 will be double of the side opposite to angle 30.

the side opposite to 60 will be√3 × the length ofthe sid eopposite to angle 30.

Hope it helps........................................