in a triangleABC angle c=3 b =2(a+b) find these angles
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let angleA=x and angleB=y then put the value and then apply sum of angle of triangle is 180 degree very simple.
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In ΔABC, we are given that ∠C=3∠B=2(∠A+∠B)
hence 3∠B/2= ∠A+∠B
We know that
(∠A+∠B)+∠C=180 (angle sum property of a triangle)
3∠B/2 +3∠B=180
3∠B+6∠B=180*2
9∠B=360
∠B= 360/9=40
Hence ∠C=3∠B=3*40
∠C=120
Also, ∠C=2(∠A+∠B)
120/2=∠A+40
∠A=60-40
∠A=20
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