Question

in a triangleABC , right angled at B ,AB =24,BC 7 find sinA ,cosA , sinC,cosC​

Answer 1

Step-by-step explanation:

Given two sides ,By Pythagoras theorem third side is 25;

Sin A = P/H =7/25

Cos A = B/H =24/25

sin C = P/H =24/25

cos C = B/H = 7/25

Answer 2

Step-by-step explanation:

$\sin( \alpha ) = \frac{7}{25} \\ \cos( \alpha ) = \frac{24}{25} \\ \sin( \gamma ) = \frac{24}{25 } \\ \cos( \gamma ) = \frac{7}{25} \\ here \: \alpha \: means \: a \: \: and \: \gamma \: means \: c$

Explanation is given in the attachment