Question

in a trianglePQR, if 3 sin P+4 cos Q =6 and 4sin Q +3 cos P =1, then the angle R is
equal to​

Answer 1

Step-by-step explanation:

Given

3sinP+4cosQ=6 -Eq 1

4sinQ+3cosP=1 -Eq 2

Eq1-Eq2

3sinP+4cosQ-4sinQ-3cosP=5