in a trianglePQR, if 3 sin P+4 cos Q =6 and 4sin Q +3 cos P =1, then the angle R is
equal to
Answers
Answered by
4
Step-by-step explanation:
Given
3sinP+4cosQ=6 -Eq 1
4sinQ+3cosP=1 -Eq 2
Eq1-Eq2
3sinP+4cosQ-4sinQ-3cosP=5
Similar questions