Question

in a triangles ABC , angle B= 110° and line bisects angleB such that BD is perpendicular to CA . What is the value of angle C

Answer 1

clearly, Triangle ABC is div. into two triangles

ABD  and CBD

so, In ΔCBD

∠C + ∠B + ∠D = 180°

Hence, ∠C = 180°-145° = 35°

Answer 2

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