In a trihybrid cross what would be the chance of getting progeny with atleast one dominant alleles in f2 generation
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Hey there!
Here's your answer.
In every hybrid self-cross (F1 cross), there is only one progeny in F2 generation which has all the recessive alleles.
(You can cross check this using punnett square)
So, if you consider the following cross
☛ AaBbCc × AaBbCc
There will be only one progeny whose genotype will be aabbcc.
Total number of progenies in the F2 generation of trihybrid cross = 4ⁿ = 4³ = 64.
If only one has all recessive alleles, then the rest 63 will have atleast 1 dominant allele.
☛ Therefore, the chance of getting atleast one dominant allele in F2 generation of trihybrid cross is = 63/64
Hope that helps.
Thanks.
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Trihybrid Cross
Explanation:
- In each hybrid self-cross (F1 cross), there is only one progeny in F2 generation which has all the recessive alleles
- There will be only one progeny whose genotype will be aabbcc. Complete number of offspring in the F2 age of trihybrid cross = 4ⁿ = 4³ = 64
- The parental generation (P) is the main arrangement of parents crossed.The F1 (first dutiful) generation comprises of all the offspring from the parents
- The F2 (second obedient) generation consists of the posterity from permitting the F1 people to interbreed
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