In a tug of war, a fat man pulls with a force of 100 N on a side, and a lean man pulls with 90 N on the other side. Determine the net force.
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Solution :
Given:
Force F1= 100 N
Force F2 = -90 N
The net force formula is given by
FNet = F1 + F2
FNet = 100 – 90
FNet = 10 N
Therefore, the net force is 10 N.
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