In a two dight number, deget ath the ten's place is twice at
digit al units's place if the number obtained by intenchalang
-ing the edlight is added to the orignal number, the Samo
is 66. find the number
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Let the digit at one's place be x
Then the digit at ten's place will be 2x
According to the question,
(10*2x)+x + (10*x)+2x= 66
21x+12x= 66
33x=66
x=2
Therefore the number is (2*2)*10 + (2)*1
= 40+2
=42
Hope it helps:)
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