in a two digit 2 digit number digit in units place is twice the digit in tens place if 27 is added to its digits are reversed find the number
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Let x be the number at the unit's place and y be the number at the ten's place.
Two digit number = 10y + x
According to the conditions,
y = 2x
2x - y = 0 ...(i)
10x + y + 10y + x = 66
x + y =11 ....(ii)
Solve (i) and (ii), we get
x = 2 and y = 4
Two digit number = 10y + x = 42
Two digit number = 10y + x
According to the conditions,
y = 2x
2x - y = 0 ...(i)
10x + y + 10y + x = 66
x + y =11 ....(ii)
Solve (i) and (ii), we get
x = 2 and y = 4
Two digit number = 10y + x = 42
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