In a two-digit, if it is known that its unit's digit exceeds its ten's digit by 2 and that the product of the given number and the sum of its digits is equal to 144, then the number is:
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Q:
In a two-digit number, if it is known that its unit's digit exceeds its ten's digit by 2 and that the product of the given number and the sum of its digits is equal to 144, then the number is :
Answer: 24
Explanation:
Let the ten's digit be x.
Then, unit's digit = x + 2.
Number = 10x + (x + 2) = 11x + 2
Sum of digits = x + (x + 2) = 2x + 2.
(11x + 2) (2x + 2) = 144
=>
=> (x - 2)(11x + 35) = 0
=> x = 2
Hence, Required Number = 11x + 2 = 24
10
Q:
In a two-digit number, if it is known that its unit's digit exceeds its ten's digit by 2 and that the product of the given number and the sum of its digits is equal to 144, then the number is :
Answer: 24
Explanation:
Let the ten's digit be x.
Then, unit's digit = x + 2.
Number = 10x + (x + 2) = 11x + 2
Sum of digits = x + (x + 2) = 2x + 2.
(11x + 2) (2x + 2) = 144
=>
=> (x - 2)(11x + 35) = 0
=> x = 2
Hence, Required Number = 11x + 2 = 24
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