Question

In a two digit natural number, the digit at the tens place is equal to the square of the digit at units place. If 54 is subtracted from the number, digits get interchanged. Find the number

Answer 1

Let the digits at units place and tens place be X and Y respectively.

Then, Original no. = 10y+x

and, also given that digits at tens place is equal to square of digit at units place.

So, Y = X^2(x square)...........(i)

Now, A/q Original no. - 54 = Interchanged digit no.

=> 10y + x - 54 = 10x + y

=> 10y-y+x-10x = 54

=> y - x = 6

=> x^2 - x - 6 = 0 {from eq.(i) }

=> x^2 -3x +2x-6=0

=> (x-3)(x+2) = 0

So, X= 3 or -2 ( But X can't be negative)

Now,Putting value of X in eq.(i),we get

Y= 9

Hence,the number is 93.

Hope it helps...

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Answer 2

Answer:

this is the answer

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