In a two digit natural number the digits differ by 1 the product of the number and the number obtained by reversing the digit is 252. find the number??? can anyone help please help guys I need your help if anyone will give answer I will mark the answer as a brainlist!!! please help guys please help !!!!!!
Answers
Answer:
THE CORRECT ANSWER IS 12 OR 21.
Step-by-step explanation:
let the numbers be x and y
as per condition actual no is 10x+y
on reversing the digits the no is 10y+x
x = y+1
or y = x+1
its the same so for consideration i am taking x = y+1
as per question:-
(10x+y)*(10y+x) = 252
[10*(y+1)+y]*[10y+y+1] = 252
[10y+10+y]*[11y+1] = 252
(11y+10)*(11y+1) =252
121y²+110y+11y+10 = 252
121y²+121y-242 = 0
121(y²+y-2) = 0
y²+y-2 = 0
using the mid-term factorisation
y²+2y-y-2 = 0
y(y+2)-1(y+2) = 0
(Y-1)(y+2) = 0
y = 1 or y = -2
since this is a number so y cannot be -2
so y = 1
NOW USING Y = 1
X = Y+1 = 1+1 = 2
THE NUMBER IS 2*10+1 =20+61 = 21
OR
1*10+2 = 10+2 = 12
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Step-by-step explanation:
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