in a two digit number difference of digits is 5 if that number divided by 2 and 2 added to the answer then original two digit number get reversed what is that number
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Let ,
The unit's digit be " y "
The ten's digit be " x "
The original number be " 10x + y "
Case I
In a two digit number , the difference of digits is 5
x - y = 5 --- (i)
Case II
If a number divided by 2 and 2 added to the answer then original two digit number get reversed
(10x + y)/2 + 2 = 10y + x
(10x + y + 4)/2 = 10y + x
10x + y + 4 = 20y + 2x
8x - 19y = -4 --- (ii)
Multiply eq (i) by 8 , we get
8x - 8y = 40 --- (iii)
Subtract eq (ii) by eq (iii) , we get
8x - 8y -(8x - 19y) = 40 - (-4)
11y = 44
y = 4
Put the value y = 4 in eq (i) , we get
x - 4 = 5
x = 9
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