Question

in a two digit number digit at the ten's place is nine times the digit at unit's place. if the number obtained by interchanging the digits is added to the original number, the sum is 110 . find the number
​

Answer 1

Answer:

THE NUMBER IS 91

Step-by-step explanation:

LET THE TWO DIGIT NUMBER BE 9xx

SO,

A.T.Q.,

9xx+x9x = 110

10(9x) + x + 10(x) + 9x = 110

90x+10x+10x = 110

110x = 110

x = 1

SO,

9x = 9

SO,

THE THE NUMBER WAS 9xx WHICH IS 91

I HOPE YOU UNDERSTOOD THE QUESTION!!!

Answer 2

Answer:

noice

Step-by-step explanation: