Question

- In a two digit number, digit at the ten's
place is twice the digit at unit's place
If the number obtained by interchanging
the digits is added to the original number
the sum is 66. Find the number.​

Answer 1

Answer:

42

Step-by-step explanation:

Let the number be 10x + y,

Then the digit in the units place is y and the digit in the tens place will be x

According to the question,

x = 2* y

Also,

When the digits in the number are interchanged, we get (10y + x)

10y + x + 10x + y = 66

11x + 11y = 66

Use x = 2y,

11* 2y + 11 y = 66

22y + 11y = 66

33y= 66

y = 66/33

y = 2

x = 2 * 2 = 4

So, the digit in the units place is 2 and

the digit in the tens place is 4

The number is 42