Question

In a two digit number, digit at the ten's place is twice the digit at units's place. If the number obtained by interchanging the digits is added to the original number, the sum is 66.

Answer 1

Answer:

42

Step-by-step explanation:

Let the tens digit be x and the units digit be y.

So the number=10x+y

According to question-

   x=2y............................................................(equation 1)

After interchanging the digits we get

  10y+x

Also,

=>(10x+y)+(10y+x)=66                            (given)

=>10x+y+10y+x=66

=>11y+11x=66

=>11(y+x)=66

=>y+x=66/11

=>y+x=6

From equation 1,  x=2y

So, y+2y=6

=>3y=6

=>y=6/3

=>y=2

And x=2(2)=4

Hence the number is 42.

Answer 2

Let tens digit is 2X
Unit digit ...... is X

Now
the Number is 10×(2X)+X

Number getting after interchanging digit= 10×(X)+2X

ATQ

20X+X+10X+2X = 66

33X=66
X=2


Ten's digit is 2×2=4
Unit's digit is 2

So the number is 42

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