Question

in a two digit number,digit at the tens place is twice the digit at units place .if the number obtained by interchanging the digits is added to the original number,the sum is 66.find the number​

Answer 1

Answer:

42 or 24

Step-by-step explanation:

Let the digit at unit place be x

Then the digit at tens place will be 2x

The number obtained is

$= (10 \times 2x) + x \\ = 20x + x \\ = 21x$

The reversed number

$= (10 \times x) + 2x \\ = 10x + 2x \\ = 12x$

A.T.Q.

$21x + 12x = 66 \\ 33x = 66 \\ x = \frac{66}{33} \\ x = 2$

So, the number is

$= 10 \times 2 \times 2 + 2 \\ = 40 + 2 \\ = 42$

Reversed number is 24

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