Question

In a two digit number digit at the tension place is twice the digit at units place.if the number obtained by interchanging the digits is added to the original number the sum is 66 find details the number

Answer 1

let the unit place no be X
tenth place no be 2X
2X+X=3X
The sum of the original number and digits interchanged no = 66
thus 3x=6
X=2
2x=4
The actual no is 24
interchanged no is 42
24+42=66
I think this is more than enough