In a two digit number,digit in the tens place is twice the digit in the units place. If the number obtained by interchanging the digit in added to the orignal number,the sum is 66 find the number.
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Answer:
The original number is 42
Step-by-step explanation:
Let digit in one's place of original number be "x"
ATQ, Digit in ten's place of original number will be "2x"
The original number is 10*(2x) + x = 20x + x = 21x
The number obtained by interchanging the digits will be:
10*x + 2x = 12x
ATQ, if the number obtained by interchanging the digits is added to the original number, the sum is 66.
=> 12x + 21x = 66
=> 33x = 66
=> x = 2
=> Digit in one's place of original number = 2
=> Digit in ten's place of original number = 4
The orginal number is 42
Verifiy:
Original number = 42
Number obtained by interchanging digits = 24
Sum of 42 + 24 = 66 (as given in the problem)
Hence, verified
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