Question

in a two digit number digit in units place is twice the digit in the tens place if 27 is added to its digits are reversed find the number​

Answer 1

Answer:

Step-by-step explanation:

Given :-

In a two digit number digit in units place is twice the digit in the tens place.

If 27 is added to its digits are reversed.

Solution :-

Let ten's digit = x  

Unit's digit = 2x

Required Number = 10x + 2x = 12x

On Interchanging the Digit's Number = 10 (2x) + x = 21x

According to The Question

⇒ 12x + 27 = 21x

⇒ 27 = 21x - 12x

⇒ 27 = 9x

⇒ 27/9 = x

⇒ 3 = x

Required Number = 12 × 3 = 36

Hence, the number​ required number is 36.

Answer 2

$\huge{\mathfrak{\red{\underline{\underline{Answer :-}}}}}$

$\LARGE{\mathrm{\gray{\underline{Assuming :-}}}}$

Let the digit which is on unit place be a.

Let the digit which is on unit place be 2a.

The Required number = 10a + 2a = 12a

When interchanging the digit's number. Then,

10 (2a) + a = 20a + a = 21a

$\LARGE{\mathrm{\gray{\underline{Solution :-}}}}$

A.T.Q

12a + 27 = 21a

Taking the a term digit to R.H.S

27 = 21a - 12a

27 = 9a

27/9 = a

3 = a

So, the required number will be 12x = 12(3) = 36

$\huge{\boxed{\boxed{\red{\underline{36}}}}}$