Question

in a two digit number sum of its digit is 11 if 45 is added to the number the digit interchange their places find the number

Answer 1

Let digits be x and y..

so it becomes10x+y

where x+y=11... (1)

When 45 is added to it.

it becomes 10y+x

Given:-10y+x-(10x+y)=45

hence, 9y-9x=45

y-x=5... (2)

Solving equation (1) and (2) simultaneously. ..

2y=16..y=8

and hence x=11-y=11-8=3

so number become 10x+y

i.e. 10 (3)+8=38

.

.Hope it helps you.

@kapilsaraswat781

Answer 2

Answer:

Hope the answer helps you....

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