in a two digit number sum of its digit is 7 if 45 is added to the number the digit interchange their places find the number
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2
Answer:
16
Step-by-step explanation:
Let the two-digit number be 10x+y.
Now, x+y=7----------1
10x+y+45=10y+x
~9x-9y=-45
~x-y=-5-----------2
Adding eq 1 and 2,
2x=2
~x=1
Therefore, y=7-1 or y=6
Therefore, the number is 10(1)+6=16
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