in a two digit number tens digit is 6 more than the units digit . if the sum of the number formed by reversing the digits is 110, find the orginal number
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Let the digits in the ten's and ones place of the required number be x and y.
Given, x =6+y
y = x-6
Since we do not know what the OG number is, we will assume that the number is 10x + y
Interchanged number = 10y + x
Also given,
(10x + y) + (10y + x )= 110
11x+11y = 110
11 ( x+y)=110/11
x+y=10
y=10-x
y=6
x=10-6
x=4
The number is 46
(46+64=110)
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tq for asking.
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