in a two digit number that tens digit is thrice the unit digit when the digits are reversed the number is reduced by 54 find the numbers
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Answered by
36
Hey
Here is your answer,
Let the Unit digit be x
and tens digit be y
Original number :- 10y + x
Reversed number :- 10x + y
• the ten's digit is three times the unit digit.
y = 3x ........ ( i )
• when the number is decreased by 54, the digits are reversed.
10y + x - 54 = 10x + y
10y - y + x - 10x = 54
9y - 9x = 54
9 ( y - x ) = 54
y - x = 54/9
y - x = 6 ..... ( ii )
Putting value of y from ( i ) in ( ii )
y - x = 6
3x - x = 6
2x = 6
x = 6/2
x = 3
Putting value of x in ( i )
y = 3x
y = 3 × 3
y = 9
The required number is 10y + x :- 93x
Hope it helps you!
Here is your answer,
Let the Unit digit be x
and tens digit be y
Original number :- 10y + x
Reversed number :- 10x + y
• the ten's digit is three times the unit digit.
y = 3x ........ ( i )
• when the number is decreased by 54, the digits are reversed.
10y + x - 54 = 10x + y
10y - y + x - 10x = 54
9y - 9x = 54
9 ( y - x ) = 54
y - x = 54/9
y - x = 6 ..... ( ii )
Putting value of y from ( i ) in ( ii )
y - x = 6
3x - x = 6
2x = 6
x = 6/2
x = 3
Putting value of x in ( i )
y = 3x
y = 3 × 3
y = 9
The required number is 10y + x :- 93x
Hope it helps you!
Answered by
2
Step-by-step explanation:
So the original number will be 93.
hope it will helps u
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