Question

In a two digit number the 10th term is three times the unit digit when the number is decreased by 4 the digits are reversed find the number

Answer 1

Answer:

Step-by-step explanation:

Let the digit at unit's place be x.

GIVEN : digit at Ten’s place = 3x

Number formed :

10 × 3x + x = 30x + x = 31x

Number formed after reversing the digits:

10 × x + 3(x )= 10x +3x = 13x

ATQ,

31x -54 = 13x [Given]

31x -13x = 54

18x = 54

x = 54/18

x= 3

Number = 31x = 31 × 3 = 93

Hence, the number is 93.

Answer 2

Hi Mate !!

Let the Unit digit be x
and tens digit be y


Original number :- 10y + x
Reversed number :- 10x + y

• the ten's digit is three times the unit digit. 

y = 3x ........ ( i )

• when the number is decreased by 54, the digits are reversed. 

10y + x - 54 = 10x + y

10y - y + x - 10x = 54

9y - 9x = 54

9 ( y - x ) = 54

y - x = 54/9

y - x = 6 ..... ( ii )

Putting value of y from ( i ) in ( ii )

y - x = 6 

3x - x = 6

2x = 6

x = 6/2

x = 3

Putting value of x in ( i )

y = 3x

y = 3 × 3

y = 9


The required number is 10y + x :- 93