In a two digit number the 10th term is three times the unit digit when the number is decreased by 4 the digits are reversed find the number
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Answer:
Step-by-step explanation:
Let the digit at unit's place be x.
GIVEN : digit at Ten’s place = 3x
Number formed :
10 × 3x + x = 30x + x = 31x
Number formed after reversing the digits:
10 × x + 3(x )= 10x +3x = 13x
ATQ,
31x -54 = 13x [Given]
31x -13x = 54
18x = 54
x = 54/18
x= 3
Number = 31x = 31 × 3 = 93
Hence, the number is 93.
Answered by
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Hi Mate !!
Let the Unit digit be x
and tens digit be y
Original number :- 10y + x
Reversed number :- 10x + y
• the ten's digit is three times the unit digit.
y = 3x ........ ( i )
• when the number is decreased by 54, the digits are reversed.
10y + x - 54 = 10x + y
10y - y + x - 10x = 54
9y - 9x = 54
9 ( y - x ) = 54
y - x = 54/9
y - x = 6 ..... ( ii )
Putting value of y from ( i ) in ( ii )
y - x = 6
3x - x = 6
2x = 6
x = 6/2
x = 3
Putting value of x in ( i )
y = 3x
y = 3 × 3
y = 9
The required number is 10y + x :- 93
Let the Unit digit be x
and tens digit be y
Original number :- 10y + x
Reversed number :- 10x + y
• the ten's digit is three times the unit digit.
y = 3x ........ ( i )
• when the number is decreased by 54, the digits are reversed.
10y + x - 54 = 10x + y
10y - y + x - 10x = 54
9y - 9x = 54
9 ( y - x ) = 54
y - x = 54/9
y - x = 6 ..... ( ii )
Putting value of y from ( i ) in ( ii )
y - x = 6
3x - x = 6
2x = 6
x = 6/2
x = 3
Putting value of x in ( i )
y = 3x
y = 3 × 3
y = 9
The required number is 10y + x :- 93
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