Question

In a two digit number the digit at one's place is three times the digit 3 at ten's place. The sum of the digits is 8. Find the number.​

Answer 1

Answer:

Let the digit at tens place be x and the digit unis place be y.

Then the original number will be 10x+y.

The digit at tens place is three times the digit at the units place.

i.e. x=3y ....(1)

The sum of this number and the number formed by reversing its digits is 88.

(10x+y)+(10y+x)=88

⇒11x+11y=88

⇒x+y=8 ....(2)

Substitute the value of equation (1) in equation (2).

Therefore, 3y+y=8

⇒4y=8

⇒y=2

Therefore, x=3y=3×2=6

Therefore, the original number is 62.

Step-by-step explanation:

PLEASE MARK AS BRILLIANT PLEASE

#нσρє íт нєℓρѕ♡~

#мαяк αѕ вяαíηℓíѕт☘️

#itz Manas here❤️✨