Question

In a two digit number ,the digit at tens place 7 and the sum of the digit 8 times the digit at units place

Answer 1

Ans is 71
Two digit number ten place no is 7
71
Sum of the digit 8 times the digit at unit place
7+1=8
Unit place 1 is 8 times of sum of the digits

Answer 2

$\huge \pink{ \underline{ \overline{ \tt \: solution}} \mid}$

Let the digit at unit's place be x

now,

If we go according to the question, then the digit at tens place is 7.

So, the required number will be = 7*10+x = 70+x ---(1)

and, it is given in the question that the sum of the digit is 8 times the digit at the unit's place

therefore,

7+x=8x

7x=7

x=1

So, the required number is;

70+1 =71

$\green {\sf{answer \: is \: 71}}$