Question

in a two digit number the digit at tens place is 7 and the sum of digit is 8 times the digit at unit place then the number is what​

Answer 1

Step-by-step explanation:

ten place digit is 7

and unit place digit be Y

two digit number=70+y

as per condition

7+y=8y

8y-y=7

7y=7

y=7/7

y=1

two digit number is 71

Answer 2

Answer:

Digit at unit place = 1, Number =71

Step-by-step explanation:

Let number at unit place = y

According to question

Number=7 (y)

7+y=8

y=8-7

y=1

Sum of digits

7+y=8y

Left Hand Side

7+y

7+1

8

Right Hand Side

8y

8×1

8

Left Hand Side is equal to Right Hand Side

Hence Verified

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