in a two digit number the digit at the tens place is equal to the square of the digit at the tens place if 18 is added to the number the digits get interchanged numbers
sahilagrawal11:
actually there was mistake..
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Heya
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Let the two digit number be xy
ACCORDING TO THE QUESTION
y = x²
10x + y +18 = 10y + x
=>
9x - 9y = -18
=>
y - x = 2
y = x² put this value of y in above equation we get
x² - x - 2 = 0
=>
x² - 2x + x - 2 = 0
=>
x ( x - 2 ) + 1 ( x - 2 ) = 0
=>
x = -1 OR x = 2
For x = -1 y = 1
For x = 2 y = 4
So, the two digit number is -11 OR 24
-11 will be rejected becoz when we interchange the digits they remain same.
So, the two digit number is 24
______________________________
Let the two digit number be xy
ACCORDING TO THE QUESTION
y = x²
10x + y +18 = 10y + x
=>
9x - 9y = -18
=>
y - x = 2
y = x² put this value of y in above equation we get
x² - x - 2 = 0
=>
x² - 2x + x - 2 = 0
=>
x ( x - 2 ) + 1 ( x - 2 ) = 0
=>
x = -1 OR x = 2
For x = -1 y = 1
For x = 2 y = 4
So, the two digit number is -11 OR 24
-11 will be rejected becoz when we interchange the digits they remain same.
So, the two digit number is 24
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