Question

in a two digit number the digit at the unit place is double the digit in the tens place . the number exceededs the sum of its digits by 18 . find the number​

Answer 1

Answer:

Here's u r answer in given attachment .

Hope it's helpful.....

Please mark it as brainliest....

Answer 2

Answer: 24

Step-by-step explanation:

Let the digit in ten's place=x

The digit in one's place= 2x

The number = (10×x)+(1×2x)= 10x+2x=12x

Sum of digits=x+2x=3x

Given in question = 3x+18=12x

=18=12x-3x=9x

=9x=18

=x =18÷9=2

So the number =(2×10)+(2×2×1)

=20+4=24

Pls mark as brainiest