Question

In a two-digit number the digit at the unit place is double the digit in the tens place.the number exceeds the sum of its digit by 18.find the number

Answer 1

let the digits at one's place be x
therefore, according to question
digit at ten's place is 2x.
therefore the number is 10(x)+2x=12x.
sum of digits =x+2x=3x


therefore according to question,
number - sum of digits=18
12x-3x=18
9x=18
x=2.

therefore number is =10(2)+2(2)=24.

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