Question

in a two digit number ,the digit at the unit place is double the digit in tens place .the number exceed the sum of its digit by 18 .find the number

Answer 1

let the ten's place be x
the units place digit is double the unit place
so unit place=2x
so the number form is x.10+2x.1
                                    10x+2x=12x
the no exceeds the sum of the digit by 18
                                          12x-2x+x=18
                                            12x-3x=18
                                                9x=18
                                              x=18/9
                                             x=2
hence the no is 24= 2.10+4.1

Answer 2

Answer:

ok

Step-by-step explanation:

24 ...,.,.,.,.,..,.,...,.,.