in a two digit number, the digit at the unit place is double the digit in the tens place. the number exceed the sum of its digit by 18. find the number?
Answers
Answered by
4
here's you answer
the number is 23
VERIFICATION*
number - sum of digits = 18
= 23 - (2+3)
= 23 - 5
23 - 5 = 18
hence, verified
HOPE IT HELPS !!!!!!!!!!!!
the number is 23
VERIFICATION*
number - sum of digits = 18
= 23 - (2+3)
= 23 - 5
23 - 5 = 18
hence, verified
HOPE IT HELPS !!!!!!!!!!!!
Answered by
2
Let the number at tens be X.
Let the no. at ones be Y
Now a two digit number form : 10x+Y.......(1)
Now according to the question.
X=2Y........(2)
So,
X+Y=18....... (3)
NOW,
X+y =18.
2y+y=18
3y=18
Y=6
Similarly 2*6=x
12=x
So the no forms10*12+6=126
Let the no. at ones be Y
Now a two digit number form : 10x+Y.......(1)
Now according to the question.
X=2Y........(2)
So,
X+Y=18....... (3)
NOW,
X+y =18.
2y+y=18
3y=18
Y=6
Similarly 2*6=x
12=x
So the no forms10*12+6=126
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