in a two-digit number,the digit at the unit place is thrice the digit in the tens place. the number exceed the sum of its digit by 27.find the number
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let the no. be 10x + y
according to the question
y = 3x
also,
10x + y = x + y + 27
9x = 27
x = 3
substituting y = 3x
hence y = 9
so the no. is 39
according to the question
y = 3x
also,
10x + y = x + y + 27
9x = 27
x = 3
substituting y = 3x
hence y = 9
so the no. is 39
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