Question

in a two digit number the digit at the unit place is thrice the digit in the tens place. the number exceeds the sum of its digit by 27. find the number

Answer 1

➡HERE IS YOUR ANSWER⬇

let the no. be 10x + y

according to the question

y = 3x

also,

10x + y = x + y + 27

9x = 27

x = 3

substituting y = 3x

hence y = 9

so the no. is 39

⬆HOPE THIS HELPS YOU⬅

Answer 2

x×10Tens digit place=x

Units digit place =3x

The number is

= (x × 10)+3x

=10x + 3x

=13x

Sum of the digits=4x

Sum of the digits of the number exceeds by 27

Then,

13x = 4x + 27

=9x = 27

x = 27/9

x = 3

Tens digit = 3

Units digit = 3x = 3 × 3=9

So,this is the answer