in a two digit number the digit at the unit place is thrice the digit at tens place the number exceeds the sum of its digit by 27 find the number ...plz solve it ..
Answers
Answered by
4
let the no. be {x.3x}.............(i)
given that (x+3x) + 27 is the no.
from (i)
x can't be 1(too small) ,4,5,6,7,8,9(too big)
if it is 2 then the no. will be 26 which is smaller than 27
it means it's 3.
the no. is 39.
Anonymous:
hiii
Answered by
0
hey mate to find the locations of 27 x=x+1/2... and the exceed point is x-n =39..
hope it's help u
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