Question

In a two digit number, the digit at the units place is double the digit in the tens place.the number exceeds the sum of its digits by 18.find the number

Answer 1

Answer:

24

Step-by-step explanation:

Given, it is a 2-digit number. Let us say that the number is xy.

Now, x is in tens place and y is in units place.

Given that, the digit at the units place is double the digit in the tens place.

So y=2x.

The sum of the digits is x+y = x+2x = 3x.

xy = Sum of digits + 18

xy = 3x + 18

x 2x = 3x + 18

Now you can take x=2...

You get, 24=6+18=24 which satisfied the above equation.

So the number is 24