Question

in a two-digit number the digit at the units place is double the digit in the tens place. the number exceeds the sum of its digits by 1.8. find the number with solutions

Answer 1

Let the tens digit of the number be x and ones digit be y.
Thus, number = 10x+y
According to question : y=2x ..............- equation ( 1 )

also 10x+y = x+y+18 
On solving this we get  x=2
putting x = 2 in equation 1 we get
y= 2x
y=2*2
y=4

thus number =10x+y=10*2+4=20+4
=24

Answer 2

Answer:

Step-by-step explanation: