In a two digit number the digit at the units place is double the digit in the tens place the number exceed the sum of its digit by 18.Find the number.
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LET THE NUMBER BE 10Y+X
HERE X IS UNIT DIGIT AND Y IS TENS DIGIT
WE ARE GIVEN THAT X=2Y
AND ALSO THAT 10Y+X=18+X+Y
PUTTING X=2Y,WE GET
10Y+2Y=18+2Y+Y
9Y=18 .AND Y=2 AND X=4
THE NO. IS 10(2)+4. =24
HOPE YOUR PROBLEM IS SOLVED.
PLEASE MARK IT BRAINLIEST ANSWER.
THANKS!
HERE X IS UNIT DIGIT AND Y IS TENS DIGIT
WE ARE GIVEN THAT X=2Y
AND ALSO THAT 10Y+X=18+X+Y
PUTTING X=2Y,WE GET
10Y+2Y=18+2Y+Y
9Y=18 .AND Y=2 AND X=4
THE NO. IS 10(2)+4. =24
HOPE YOUR PROBLEM IS SOLVED.
PLEASE MARK IT BRAINLIEST ANSWER.
THANKS!
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ya sir
:-)
sir...first read the question...
okay
wait
aditya sir ur ans is right
yes.it can also be checked whether it satisfies the given condition
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