Question

In a two digit number, the digit at the units place is double the digit in the tens place. The number exceeds the sum of its digits by 18. Find the number.​

Answer 1

Step-by-step explanation:

Answer:

The given two digit number is found out to be 24.

To find:

Two digit number = ?

Solution:

Given :  

Assuming a number with two digits, the digit at the units place is double the digit in the tens place. The number exceeds the digit’s sum by 18.  

1. Assume the 1st digit number at tens place as a.  

In a two digit number, the digit at the units place is double the digit in  the tens place.  

Then, the 2nd digit number at ones place will be 2a.

The number together to be written = 10a + 2a = 12a

2. The number exceeds the digits sum by 18.  

Sum of the digits = a + 2a = 3a

12a = 3a + 18

12a - 3a = 18

9a = 18

a = 2 i.e. the number at tens' place.

We know that the 2nd digit number at ones' place is 2a = 2(2) = 4.

Hence, the number is 24

Answer 2

$\sf{\huge{\purple{\mathfrak{\underline{\underline{Question}}}}}}$

• In a two digit number, the digit at the units place is double the digit in the tens place. The number exceeds the sum of its digits by 18. Find the number.

$\sf{\huge{\purple{\mathfrak{\underline{\underline{Solution}}}}}}$

Let, the digit at tens place be x and the digit at units place be y

therefore the original no. = 10x + y

sum of the digits = x + y

ATQ :-

10x + y = x + y + 18

10x - x + y - y = 18

9x = 18

x = $\dfrac{18}{9}$

x = 2

ATQ :-

y = 2x

y = 2 x 2

y = 4

original no. = 10x + y = 10 x 2 + 4

original no. = 20 + 4 = 24

$\sf{\bold{\red{\boxed{original \: no. = 24}}}}$

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